If i have to move the constant over to one side, what value would i have to add to the left side in order to complete the square?

x² + 4x - 5 = 2

To make the equation complete square , we have to add 11 .

Step-by-step explanation:

Given as :

The linear equation is

x² + 4 x - 5 = 2

Now, move the constant to left side of equation

So, x² + 4 x - 5 - 2 = 0

Or, x² + 4 x - 7 = 0

Now, to make equation complete square , let add 11 both side

So, x² + 4 x - 7 + 11 = 11

Or, x² + 4 x + 4 = 11

Now, applying mid-term break

So,  x² + 2 x + 2 x + 4 = 11

Or, x ( x + 2) + 2 (x + 2) = 11

Or, (x + 2) ( x + 2) = 11

Or, (x + 2)² = 11

Hence, To make the equation complete square , we have to add 11 . Answer

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.