The net weights (in grams) of a sample of bottles filled by a machine manufactured by edne, and the net weights of a sample filled by a similar machine manufactured by orno, inc., are:

edne 8 7 6 9 7 5
orno 10 7 11 9 12 14 9 8

testing the claim at the 0.05 level that the mean weight of the bottles filled by the orno machine is greater than the mean weight of the bottles filled by the edne machine, what is the critical value? assume equal standard deviations for both samples.

a. +2.179
b. +2.145
c. +1.782
d. +1.761

Since is a right tailed test we need to look on the t distribution with 12 degrees of freedom that accumulates 0.05 of the area on the right. And we can use the following excel code:

"=T.INV(0.95,12)" and we got

Step-by-step explanation:

When we have two independent samples from two normal distributions with equal variances we are assuming that  

And the statistic is given by this formula:

Where t follows a t distribution with degrees of freedom and the pooled variance is given by this formula:

This last one is an unbiased estimator of the common variance

The system of hypothesis on this case are:

Null hypothesis:

Alternative hypothesis:

Or equivalently:

Null hypothesis:

Alternative hypothesis:

Our notation on this case :

represent the sample size for group Edne

represent the sample size for group Orno

represent the sample mean for the group Edne

represent the sample mean for the group Orno

represent the sample standard deviation for group Edne

represent the sample standard deviation for group Orno

First we can begin finding the pooled variance:

And the deviation would be just the square root of the variance:

And now we can calculate the statistic:

Now we can calculate the degrees of freedom given by:

Since is a right tailed test we need to look on the t distribution with 12 degrees of freedom that accumulates 0.05 of the area on the right. And we can use the following excel code:

"=T.INV(0.95,12)" and we got

Since our calculated value is higher than the critical value we have anough evidence to reject the null hypothesis, and on thsi case the mean for Orno is significanlty higher than the mean for Edne at 5% of significance.

the answer is $42.96

step-by-step explanation: