In 1992, the moose population in a park was measured to be 3570. by 1999, the population was measured again to be 3640. if the population continues to change linearly:

find a formula for the moose population,
,p, in terms of ,t, the years since 1990.

The formula for the moose population is

Step-by-step explanation:

In 1992—that is, 2 years after 1990 or at —the population is 3570, and in 1999 () population is 3640; so we have

Now the formula that will model the moose population will be of the form:

The slope is

therefore we have

Now we know that at , so we put these values in and solve for

With this value of , we finally have the formula for the moose population:

i think the answer is fried chicken ; >

step-by-step explanation:

answer: 7 x 2/5 = 2.8 hours, is your answer. your welcome! : 3

step-by-step explanation: first work out how long it took to hose 1/7 of the lawn which is 2/5 hours. times that by 7 to get the whole lawn.

sorry i don't know the other answer. i didn't learn what a proportional relationship is.