Ms. wang is shopping for a new refrigerator. brand a costs $569 and uses 635 kilowatt-hours per year. brand b costs $647 and uses 582 kilowatt-hours per year. if electricity costs $0.18 per kilowatt-hour, how much would ms. wang save on electricity per year by buying brand b?

Savings on electricity per year by brand B = 114.3 - 104.76 = $9.54

Step-by-step explanation:

Ms. Wang is shopping for a new refrigerator. Brand A costs $569 and uses 635 kilowatt-hours per year. Brand B costs $647 and uses 582 kilowatt-hours per year.

Let's assume he buys brand B, so he already has a loss over the price of the commodity that is , loss = 647 - 569 =$78

Cost of electricity = $0.18

Now in the case of electricity,

spending on Brand A = 635 0.18 = $114.3

spending on Brand B = 582 0.18 = $104.76

Savings on electricity per year by brand B = 114.3 - 104.76 = $9.54

true

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