10. divide the problems below among your group, and find the sample proportion of successes and the estimated margin of error in each situation:
a. sample of size 20, 5 red chips
b. sample of size 40, 10 red chips
c. sample of size 80, 20 red chips
d. sample of size 100, 25 red chips

a) 0.1936

b) 0.137

c) 0.097

d) 0.087

Step-by-step explanation:

Margin of error is given as:

E =  

here,

p is the probability of event

n is the sample size

a. Sample of size 20, 5 red chips

n = 20

p = 5 ÷ 20

= 0.25

Thus,

E =  

or

E = 0.1936

b. Sample of size 40, 10 red chips

n = 40

p = 10 ÷ 40

= 0.25

Thus,

E =  

or

E = 0.137

c. Sample of size 80, 20 red chips

n = 80

p = 20 ÷ 80

= 0.25

Thus,

E =  

or

E = 0.097

d. Sample of size 100, 25 red chips

n = 100

p = 25 ÷ 100

= 0.25

Thus,

E =  

or

E = 0.087

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²