find the area of the circle

π9x^6y^2

Step-by-step explanation:

A = πr^2

r = 3x^3y

A = π(3x^3y)^2

A = π9x^6y^2

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

c. (3,2,6) is the answer.