Achemist wants to mix a 70% saline solution with a 8 liters of a 25% saline solution to create a solution with 40% salt. how many liters of the 70% solution does she need.

The quantity of 70% saline solution chemist need is 4 liters

Step-by-step explanation:

Given as :

The quantity of 25% saline solution = 8 liters

Let The quantity of 70% saline solution chemist need = x liters

The quantity of 40% saline solution mixture = (x+8) liters

Now, According to question

∵The mixture is created with solutions

So, 25% of quantity of saline + 70% of quantity of saline = 40% of quantity of mixture

Or, 25% of 8 liters + 70% of x liters = 40% of (x+8) liters

Or, × 8 + × x =   × (x+8)

Or, + =

Or, 200 + 70 x = 40 × (x+8)

Or, 200 + 70 x = 40 x + 320

Or, 70 x - 40 x = 320 - 200

Or, 30 x = 120

∴  x =

i.e x = 4 liters

So,The quantity of 70% saline solution chemist need = x = 4 liters

Hence, The quantity of 70% saline solution chemist need is 4 liters Answer

50x5=$250

step-by-step explanation:

i need points

step-by-step explanation:

sorry bubs