In the triangle abc, if side a is 3, side b is 4 and side c is 5, what is the cosine of the smallest angle?

Cosine of the smallest angle is 4/5.

Step-by-step explanation:

It is given that in the triangle ABC,  side a is 3, side b is 4 and side c is 5.

Sum of squares of two smaller sides.

Sum of squares of largest sides.

Since sum of squares of two smaller sides is equal to sum of squares of largest sides, therefore triangle ABC is a right angle triangle.

Hypotenuse = 5 units.

In a right angle triangle, the smallest angle has shortest opposite side.

Shortest side is a=3 It means angle A is smallest.

Therefore, the cosine of the smallest angle is 4/5.

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

i'm not really sure how to answer that

step-by-step explanation: