Two planes leave an airport at the same time, one traveling east at 250 miles/hr and the other traveling southwest at 300 miles/hr. how far apart are they after 3 hours?

They would be 1525.48 miles apart.

Step-by-step explanation:

Given,

Speed of first plane = 250 miles/hr,

∵ Distance = speed × time,

So, the distance covered by the plane after 3 hours = 250 × 3 = 750 miles,

Similarly, speed of second plane = 300 miles/hr,

Distance covered by the plane after 3 hours = 300 × 3 = 900 miles,

Now, first plane is going east direction while other one is going towards southwest  direction,

That is, the angle between them = 90° + 45° = 135°,

if x be the distance between them after 3 hours,

Using cosine law,

Hence, they would be 1525.48 miles apart after 3 hours.

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.

i pretty sure it is