Solve |y - 2|< 10

a.) {y|-8 < y < 12}
b.) {y|-12 < y < 8}
c.) {y|-8 < y < 8}

OPTION A

Step-by-step explanation:

We have:

Adding 'a' to the components:

- b + a < x < b + a

This is the result.

Here, we have: |y - 2| < 10

⇒ -10 < y - 2 < 10

Adding 2, we get:

- 10 + 2 < y < 10 + 2

⇒ - 8 < y < 12

That is, 'y' can take any value between -8 and 12.

In set notation: {y : - 8 < y < 12} : OPTION A is the answer.

whats the

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation: