An arrow is launched upward with a velocity of 320 feet per second from the top of a 45-foot building. what is the maximum height attained by the arrow?

Step-by-step explanation:

At maximum height velocity is zero

We have equation of motion v² = u² + 2as

     Initial velocity, u = 320 ft/s = 97.536 m/s

     Final velocity, v = 0 m/s    

     Acceleration, a = -9.81 m/s²

     Substituting

                      v² = u² + 2as

                      0² = 97.536² + 2 x  -9.81 x s

                      s = 484.88 m

    So the arrow further a height of 484.88 m

Total height = 320 + 484.88 = 804.88 m

Maximum height reached is 804.88 m

the first one

step-by-step explanation:

just id the test.