Mathematics, 07.01.2020 23:31 court3138
Given the function f(x) = 20(1.25)^x . what is the average rate of change between f(2) and f(5)
Answers: 3
![\bf slope = m = \cfrac{rise}{run} \implies \cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby \begin{array}{llll} average~rate\\ of~change \end{array}\\\\[-0.35em] \rule{34em}{0.25pt}\\\\ f(x)= 20(1.25)^x\implies f(x) = 20\left( \cfrac{5}{4} \right)^x\qquad \begin{cases} x_1=2\\ x_2=5 \end{cases}\implies \cfrac{f(5)-f(2)}{5-2}](/tpl/images/0446/0038/ad879.png)
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Given the function f(x) = 20(1.25)^x . what is the average rate of change between f(2) and f(5)...
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