7) the curve and the line given by the equations
kx^2- xy+ (k + 1).x = 1
-k/2x+y=1
where k is a non-zero constant, intersect at a single point.
a find the value of k.

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right

the answer is 11.2 (i know i’m late)

4.5%

step-by-step explanation:

6 equilateral triangles