There is a population of 1,000,000 bacteria in a colony. if the number of bacteria doubles every 270 hours, what will the population be in 810 hours from now?

8000000 bacteria

Step-by-step explanation:

We would apply the formula,

y = ab^t

Where

A represents the initial amount of bacteria.

t represents the doubling time.

From the information given

A = 1000000

t = 270 hours

Since after 270 hours, the population doubles, then

y = 2 × 1000000 = 2000000

Therefore

2000000 = 1000000 × b^270

2 = b^270

Raising both sides of the equation by 1/270, it becomes

2^(1/270) = b

The equation becomes

y = 1000000 × 2^(1/270) ×t

y = 1000000 × 2^(t/270)

Therefore, the population in 810 hours hours time would be

y = 1000000 × 2^(810/270)

y = 1000000 × 2^3

y = 8000000 bacteria

for the first question it would be the second answer for the second question it would be the third answer and for the third question it would be the first answer

step-by-step explanation: