Abig ship drops it’s anchor. e represents the anchor’s elevation relative to the water’s surface (in meters) as function of time t (in seconds). e=-2.4t+75 how far does the anchor drop every 5 seconds? answer should be meters

63 meters from the ship.

Step-by-step explanation:

A big ship drops its anchor. E represents the anchor’s elevation relative to the water’s surface (in meters) as a function of time t (in seconds) then  

E = - 2.4t + 75 (1)

Now, we have to calculate the depth of the anchor after 5 seconds of dropping from the ship.

Therefore, E = - (2.4 × 5) + 75 = 63 meters from the ship. (Answer)

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: