O
these are the means and standard deviations for samples of heights from
two kinds of trees.
tree a
mean: 25 ft
standard deviation: 5 ft
tree b
mean: 60 ft
standard deviation: 12 ft
rol
o
.
select the two true statements.
oh
cts
(
dc)
i
a. tree a's heights are less spread out than tree b's heights.
o
b. tree a has a lower average height than tree b.
o
c. tree a's heights are more spread out than tree b's heights.
d tree a has a greater average height than tree b
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The true statements are:

A. Tree A's heights are less spread out than tree B's heights and

B. Tree A has lower average height than tree B

Explanation:

Standard deviation in this case represents the spreading out of heights of the trees, Since tree A has lesser standard deviation given equal to 5 , it is less spread out than B given equal to 12, hence option A. is true.

The average of a quantity is given by mean so, the average height can be compared by the given mean values of the trees. Since, A has lesser mean value (= 25) than B(=60), tree A is said to have lower average height than tree B hence option B. is true.

5104.38 inches

step-by-step explanation:

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.