Consider the linear system of equations y = 2/5x - 1 and 2x -3y + 1 = 0

The solution is the point (-5,-3)

Step-by-step explanation:

The complete question is

Consider the linear system of equations y = 2/5x - 1 and 2x -3y + 1 = 0

The solution of the system of equations is?

we have

----> equation A

----> equation B

Solve by substitution

substitute the equation A in equation B

solve for x

Multiply by 5 both sides to remove the fraction

subtract 20 both sides

divide by 4 both sides

Find the value of y

The solution is the point (-5,-3)

the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

the root or roots of a polynomial are the values of the variable that makes the polynomial equal to 0. we can find the roots of a polynomial making the expression equal to 0 and then, isolating the variable (it it has just one variable).

for example, given the following polynomial:

the root or zero of the polynomial, can be found by making the expression equal to 0, and then, isolating the variable, so, finding the root we have:

therefore, we have that the root of the polynomial is equal to 2.

we must remember that the number of roots that a polynomial can have, will depend on the degree of the polynomial, a first degree polynomial have will have one single root, a second degree polynomial (quadratic expression) may have two roots and so.

hence the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

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