Which equation represents the line that is perpendicular to graph of 4x+3y=9 and passes through (-2,3)

The equation that represents the line that is perpendicular to 4x+3y=9 and passes through the point, (-2,3) is:

Recall:

First, rewrite 4x+3y=9 in slope-intercept form to find the slope.

4x+3y=9

3y = -4x + 9

y = -4/3x + 3

The slope of 4x+3y=9 is -4/3.

The line that is perpendicular to 4x+3y=9 will have a slope of 3/4 (negative reciprocal of -4/3).

To write the equation of the line that is perpendicular to 4x+3y=9  and passes through the point, (-2,3), substitute (a, b) = (-2,3) and m = 3/4 into y - b = m(x - a):

y - 3 = 3/4(x - (-2))

y - 3 = 3/4(x + 2) (point-slope form)

y - 3 = 3/4x + 3/2

y = 3/4x + 3/2 + 3

y = 3/4x + 9/2 (slope-intercept form)

The equation that represents the line that is perpendicular to 4x+3y=9 and passes through the point, (-2,3) is:

Learn more about equation of perpendicular lines on:

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answer: 370

step-by-step explanation:

remember use pemdas! there are no parentheses or exponents so lets move onto the first part of the equation: multiplication and division. first, lets break the first part of the equation up into something easier using the distributive property. 28 * 12= (20 *12) + (8*12) you know that 20*12 is 240 and 8*12 is 96. add them and you get 336. then, lets solve the last part of the equation (the last part of pemdas is addition and subtraction). 336 plus 34 is 370. hope this !