The width of a rectangular card is 2 cm lekss than the tength. the area is 15 cm. find the length and
width

Step-by-step explanation:

Area A = 15square cm

Length L = x

Width w = x - 2

Area = L × w

15 = x(x - 2)

15 = x^2 -2x

x^2 -2x - 15 = 0

Solving by factorization

x^2 - 5x + 3x - 15 = 0

(x^2 -5x) + (3x -15) = 0

x(x - 5) + 3(x - 5) = 0

(x + 3)(x - 5) = 0

(x + 3) = 0 or (x - 5) = 0

x = -3 or 5

Since x can't be negative therefore x is 5cm

Length = 5cm

Width = 5-2 = 3cm

(c, 0) i might be wrong so don't put full faith on my answer

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet