Answers: 1
![[0,3]](/tpl/images/0443/4458/a909d.png)
be differentiable on the open interval 
and continuous on the closed interval ![[a,b]](/tpl/images/0443/4458/f2a2f.png)
. Then if 
, then there is at least one point 
where 
.
for which 
became zero.
![x_{1}=\frac{1+\sqrt{19}}{3}=1.786\\\\and\ 1.786\ is\ in\ [0,3]](/tpl/images/0443/4458/af49c.png)
where 
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