18. point p is chosen at random on eh. find the probability that p is on fg.

Step-by-step explanation:

The total length of this line is 15 units. FG is 6 units long.

This means that the probability of p being on FG would be which can be simplified to

2/5

Step-by-step explanation:

Line EH has three line segments:

EF which measure 4

FG which measures 6

GH which measures 5

The total measure of the line (EH) = 4 + 6 + 5 = 15

So if we are calculating the probability of landing on FG,

6 / 15

Reduce the fraction to make,

2 / 5

none of these

step-by-step explanation:

23 + 34 add up to 57 so just inform the teacher of this really stupid mistake

step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.