find the probability that a point chosen at random lies in the shaded region.

0.60

Step-by-step explanation:

Again, we have a 10x10 space, which means there are 100 squares.

In this case, there are 60 shaded squares. This gives the probability of which simplifies to 0.60

0.60

Step-by-step explanation:

Because there are 100 squares and 60 out of it is shaded if you chose a random point amongst these 100 square the probability of choosing a shaded one is 60/100 which is equal to 0.60.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2