Find the exact values of sin 2θ and cos 2θ for sin θ= 5/11 on the interval 0° ≤ θ ≤ 90°
pls asap!

Below in bold.

Step-by-step explanation:

sin ^2x + cos ^2 x = 1, so

cos^2x = 1 - (5/11)^2 = 96/121

cos x = √96/11

= 4√6/11.

sin 2x = 2 sinx cosx  = 2 * 5/11 * 4√6/11.

= 40√6/121.

cos2x =  2cos^2 x - 1

= 2 * 96/121 - 1

=  192/121 - 121/121

= 71/121.

go on the tube you might find some information there

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18