you randomly choose one of the tiles. without replacing the first tile, you

choose a second tile. find the probability of the dependent event(s) both

occurring.

1/2/3/4/5/6/7

-

choosing a 6 and then a prime number

choosing two odd numbers

Choosing a 6 and then a prime number: 2/21

Choosing two odd numbers: 2/7

Step-by-step explanation:

Choosing a 6 and then a prime number:

The probability of choosing 6 out of 1, 2, 3, 4, 5, 6 and 7 is one event divided by number of total events (which is equal to 7). That results in 1/7. Once 6 is chosen, the probability of choosing a prime number (prime number is a number that can only be divided by 1 and itself) out of 1, 2, 3, 4, 5 and 7 is 4/6 (prime numbers are 2, 3, 5, 7 in total there are 4 number and total number of events are 6). Finally, the probability of choosing a 6 and then a prime number is (1/7)*(4/6)=2/21.

Choosing two odd numbers:

The probability of choosing 1st odd number is 4/7 (number of odd numbers is 4 which includes 1, 3, 5, 7 and the number of total events is 7). Once 1st odd number is chosen, the probability of choosing 2nd odd number is 3/6 (number of odd numbers is 3 - because 1 odd number is already chosen and the number of total events is 6). Finally, the probability of choosing two odd numbers in a sequence is (4/7)*(3/6)=2/7.

answer: 12

step-by-step explanation:

because yes