What is the value of secant theta given the diagram below? a unit circle is shown. a ray intersects point (negative 3, 6) in quadrant 2. theta is the angle formed by the ray and the x-axis in quadrant 1. negative startroot 5 endroot negative startfraction startroot 5 endroot over 2 endfraction startfraction startroot 5 endroot over 2 endfraction startroot 5 endroot

- √5

Step-by-step explanation:

Given that, a ray intersects point (negative 3, 6) in quadrant 2 and we are told to find the value of secant theta.

To get the answer to the question,  

The first step is to find the hypotenuse, we have to use the Pythagoras theorem  where, Hypotenuse = opposite raise to power two + adjacent raise to power.  

(I.e. h= O² + A²)

H = 6² + (-3)2

H = 36 + 9

H = 45

We then convert the answer to surds form.  

H = 3√5

The next step is to find the value of secant theta.  

To get the value of secant theta we will have to divide the hypotenuse by adjacent with a negative sign because of the negative sign in the second quadrant  

We have  

Sec ø = - (hypotenuse/adjacent)  

Sec ø = - (3√5/ 3)

Sec ø = - √5

answer: it actually depends on which is the independent variable and which is the dependent variable. let us say we're looking at a linear equation. y=2x+3. we theoretically could switch the equation to be x=(y-3)/2 and it would be the same line. so either a causes b or it can be that b causes a. so technically the answer is false

step-by-step explanation: