If five times the smaller of two numbers is subtracted from twice the larger the result is 16 if the larger is increased by three times the smaller the result is 63 by the numbers

Smaller Number = 10

Larger Number = 33

Step-by-step explanation:

Let the smaller number be "x" and the larger number be "y"

5 TIMES smaller is SUBTRACTED from TWICE larger, the result is 16, we can write:

2y - 5x = 16

and

Larger increased by 3 TIMES SMALLER, result is 63, so we can write:

y + 3x = 63

We can write this in terms of x, as:

y = 63 - 3x

Now we put this in equation 1 and solve for x first:

2y - 5x = 16

Now,

y = 63 - 3x

y = 63 - 3(10)

y = 63 - 30

y = 33

Smaller Number = 10

Larger Number = 33

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation: