State the vertical asymptote of the rational function. f(x)=(x-6)(x+6)/x^2-9.
x=6,x=-6
x=3,x=-3
x=-6,x=6
none

x = 3, x = -3

Step-by-step explanation:

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non zero for these values then they are vertical asymptotes.

Solve : x² - 9 = 0 ⇒ x² = 9 ⇒ x = ± 3

The vertical asymptotes are x = - 3 and x = 3

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