Louisiana biologists tagged 250 fish in the oxbow lake false river on october 5. on a later date, they found 7 tagged fish in a sample of 350 fish. estimate the total number of fish in false river to the nearest hundred.

at a school, the school population is 2/5 boys. there are 450 boys in the school. how many total students are in the school?

a bag contains quarter and dimes in a ratio of 3: 5. if there is $6 in quarters in the bag, how many dimes are there?

1. Set up a ratio:

7 tagged / 350 fish = 250 tagged / x fish

Solve for x:

x = (350 * 250) / 7

x = 12,500 fish

2. Divide number of boys by the population ratio:

450 / 2/5 =  (450 *5) /2 = 2250 / 2 = 1125 total students.

3.  4 quarters = $1, so they have 24 quarters total.

The ratio 3:5 means for every 3 quarters there are 5 dimes.

24 quarters / 3 = 8

8 x 5 = 40 dimes.

(1)  The population of fish in the False river is 12500.

(2) There are 1125  total number of students in the school .

(3) There are 40 dimes in the bag.

(1) Number of fish tagged by Louisiana biologists =  250

On the next day a sample was collected from the False river

The number of fish in the sample = 350

Number of tagged fish in the sample =  7

Let the population of fish in the False river  = P

Takin the ratio we can

So the population of fish in the False river = 12500

(2) The number of boys in the school = 450

Let the total number of students in the  school be B

According to the given condition

So the total number of students in the school = 1125

(3) Let the number of dimes in the bag be x

According to the given condition we can write

Also  it is given that there are $6 in quarters in the bag.

$1 = 4 quarters

So $6 has  

So we can put this value in equation (1)

So we can conclude that there are 40 dimes in the bag.

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36 girls

step-by-step explanation:

the 48 boys is 4 parts of the ratio

divide 48 by 4 to obtain one part of the ratio

= 12 ← 1 part of the ratio

3 parts = 3 × 12 = 36 ← number of girls

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15