Two congruent 30-60-90 triangles are placed, as shown, so that they overlap partly and their hypotenuses coincide. if the hypotenuse is 12 cm, find the area common to the both triangles.

The area common to both triangle is 31.77 sq. cm.

Step-by-step explanation:

Since we have given that

30-60-90 triangles are placed.

So, the ratio of sides would be

Since Hypotenuse = 12 cm

So, it becomes,

So, Base would be

and Perpendicular would be

So, Area common to the both triangles would be

Hence, the area common to both triangle is 31.77 sq. cm.

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation:

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation: