The length of a rectangle is twice the width of the rectangle the length of a diagonal of the rectangle is 25cm work out the ares of the rectangle give your answer as an integer

Area is 50 cm^2

Step-by-step explanation:

Let L represent the length of the rectangle.

Let W represent the width of the rectangle.

The formula for determining the area of a rectangle is expressed as

Area = LW

The length of a rectangle Is twice the width of the rectangle. This means that

L = 2W

The length of a diagonal of the rectangle is 25cm. This is the hypotenuse of the right angle triangle that is formed. Applying Pythagoras theorem,

25^2 = L^2 + W^2 - - - - - - - 1

Substituting L = 2W into equation 1, it becomes

25^2 = (2W)^2 + W^2

25^2 = 4W^2 + W^2 = 5W^2

Taking square of both sides,

W = √25 = 5

L = 2W = 3×5 = 10

Area = LW = 10×5 = 50 cm^2

i cant answer this, theres no table. sorry man

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i dont understand

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