Will give !
let f(x) = 36x^5 − 44x^4 − 28x^3 and g(x) = 4x^2. find f(x)/g(x) .
a. 9x^2 − 11x − 7
b. 9x^2 + 11x + 7
c. 9x^3 − 11x^2 − 7x
d. 9x^3 + 11x^2 + 7x

Step-by-step explanation:

option C is the correct answer

Step-by-step explanation:

f(x) = 36x^5 − 44x^4 − 28x^3

g(x) = 4x^2

We want to determine f(x)/g(x). It becomes

(36x^5 − 44x^4 − 28x^3) /(4x^2)

Looking at the numerator, each term in the numerator can divide the term in the denominator without remainder. it means that the term in the denominator is a common factor of the numerator and thus, 4x^2 can be factorized out of the numerator. It becomes

4x^2(9x^3 − 11x^2 − 7x) /(4x^2)

4x^2 in the numerator cancels out 4x^2 in the denominator. It becomes

9x^3 − 11x^2 − 7x

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.