5. use the properties of logarithms to condense: 3 in x – 2 in (x + 1)

Step-by-step explanation:

The given expression is

3In x – 2In (x + 1)

We would apply the rule of logarithm which is expressed as

ylog x = logx^y

Therefore,

3In x – 2In (x + 1) = lnx^3 - ln(x + 1)^2

We would apply another rule of logarithm which is expressed as

loga - logb = loga/b

Therefore

lnx^3 - ln(x + 1)^2 = ln x^3 /(x + 1)^2

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

the correct answer is 5 6 and 7