a. what would be the cost of the standard daily rate plus mileage plan?
b. what would be the cost of the unlimited mileage plan?
c. which is the better plan? _

Part a)

Part b)

Part c) Standard Daily Rate plus Mileage plan

Step-by-step explanation:

Part a) What would be the cost of the Standard Daily Rate plus Mileage plan?

Let

y ----> the total cost

x ----> the number of kilometers

we have that

For a Luxury car

For x=400 km

substitute

Part b) What would be the cost of the Unlimited Mileage plan?

we know that

The Unlimited Mileage plan for a Luxury car is $105 per day (see the table)

The trip are three days

so

To find the total cost multiply $105 by 3

Part c) Which is the better plan?

Compare

therefore

For this trip the better plan is the Standard Daily Rate plus Mileage plan

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong