Assume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00 degrees°c. a thermometer is randomly selected and tested. draw a sketch and find the temperature reading corresponding to upper p82, the 82nd percentile. this is the temperature reading separating the bottom 82% from the top 18 %.

0.915

Step-by-step explanation:

Given that the readings of  the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00 degrees°C.

Let X represent the reading of the thermometer

X is N(0.1)

Or X is a standard normal variate

we have to find 82nd percentile

i.e. we find z such that

Sketch is attached

82nd percentile is 0.915

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^