What is the smallest zero for the function(x)=4x^2-8x-60

A zero is when the y value of the equation is 0.

So we need to solve this equation.

4x²-8x-60=0

We can solve by factoring.

4(x²-2x-15)=0

x²-2x-15=0

(x+3)(x-5)=0

x=-3 and 5

the smallest zero will be -3

i will take them

step-by-step explanation:

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°