The formula used to compute a confidence interval for the mean of a normal population when n is small is the following.

x^^\_ +/-\(t text( critical value)\)s/sqrt(n)

what is the appropriate t critical value for each of the following confidence levels and sample sizes? (round the answers to two decimal places.)

(a) 90% confidence, n = 17

(b) 90% confidence, n = 12

(c) 99% confidence, n = 24

(d) 90% confidence, n = 25

a)

b)

c)

d)

Step-by-step explanation:

We are given the following information in the question:

Confidence interval:  

We have to find the appropriate t critical values for each of the following confidence levels and sample sizes:

a) 90% confidence, n = 17

Degree of freedom = n - 1 = 16

b) 90% confidence, n = 12

Degree of freedom = n - 1 = 11

c) 99% confidence, n = 24

Degree of freedom = n - 1 = 23

d) 99% confidence, n = 25

Degree of freedom = n - 1 = 24

option: d is correct

step-by-step explanation:

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58