Which point belongs to the graph of 3x-5y=1
a. (-2/3, -1/5)
b. (-2/3,1/5)
c. (2/3, -1/5)
d. (2/3, 1/5)

D. (2/3,1/5)

Step-by-step explanation:

To know which one belongs to the graph of 3x-5y = 1, we will evaluate the function with the options given

3x - 5y = 1

A. x = -2/3    y = -1/5

3(-2/3) - 5(-1/5) = 1

-2 - (-1) = 1

-2 + 1 = 1 wrong

B. x = -2/3    y = 1/5

3(-2/3) - 5(1/5) = 1

-2 - 1 = 1

-2 - 1 = 1 wrong

C. x = 2/3    y = -1/5

3(2/3) - 5(-1/5) = 1

2 - (-1) = 1

2 + 1 = 1 wrong

D. x = 2/3    y = 1/5

3(2/3) - 5(1/5) = 1

2 - 1 = 1

2 - 1 = 1 CORRECT

if we achieve equality it means that the point belongs to the graph

Step-by-step explanation:

We want to determine the solution to the equation, 3x-5y=1

We will check by substituting values of x and y into the left hand side of the equation and the values that satisfy the equation would be the solution.

1) substituting x = - 2/3 and y = -1/5 into the equation, it becomes

3 × -2/3 -5 × 1/5 = - 3

(-2/3, - 1/5) doesn't belong to the graph.

2)substituting x = - 2/3 and y = 1/5 into the equation, it becomes

3 × -2/3 -5 × -1/5 = - 3

(-2/3, 1/5) doesn't belong to the graph.

3) substituting x = 2/3 and y = - 1/5 into the equation, it becomes

3 × 2/3 -5 × -1/5 = 3

(2/3, -1/5) doesn't belong to the graph.

4) substituting x = 2/3 and y = 1/5 into the equation, it becomes

3 × -2/3 -5 × -1/5 = 1

(2/3, 1/5) belongs to the graph