Laura is 3 times as old as maria was when laura was as old as maria is now. in 2 years laura will be twice as old as maria was 2 years ago. how old are they now?

Laura is 30 years old and Maria is 18 years old.

Step-by-step explanation:

Let x be the present age of Laura and y be that of Maria.

Laura was 3 times older than Maria when Laura had Maria's present age.

Lets say Laura had Maria's present age(y) k years before.Then Maria's age at that time will be y-k where k=(x-y).

Then:

y=3(y-k)

y=3(y-(x-y))

y=3(2y-x)

3x=5y  1

After two years Laura will become x+2 years old and 2 years ago Maria was y-2 years old. Then:

x+2=2(y-2)

x=2y-62

Solving 1 and 2 we get:

x=30 and y=18

Hence Laura's present age is 30 and Maria's present age is 18.

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

answer: 40.95

step-by-step explanation: