70 find the horizontal and the vertical components of f.

(-1.22,- 6.89)

Step-by-step explanation:

The vector F lies in the IVth quadrant so the values of x and y components will be negative .

Considering the origin O and  F making an angle ∅ of 10° with the x- axis at X . Δ XOF is a right angled triangle with right angle at XF. Let XF be the perpendicular OX base and OF  hypotenuse c= 17.

So the rectangular components Fx and Fy can be found by the following formula

Sin∅ = Perpendicular/ Hypotenuse

Perpendicular = sin∅ * hypotenuse

Fy= sin - 10° *7

Fy =- 0.17364*7= -1.21554 ≅  -1.2155 ≅  -1.22

Base/ Hyptenuse= Cos∅

Base= Cos ∅ *Hypotenuse

Fx= Cos -10 ° *7= -0.98480 *7= - 6.8936 ≅   -6.894 ≅   -6.89

The rectangular components of F are Fx along x- axis and Fy along y- axis having values  equal to 1.22 and 6.89  and since they are in the fourth quadrant their values are negative

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w