Two different simple random samples are drawn from two different populations. the first sample consists of 30 people with 16 having a common attribute. the second sample consists of 1900 people with 1337 of them having the same common attribute. compare the results from a hypothesis test of p 1 equals 2 (with a 0.01 significance level) and a 99% confidence interval estimate of p 1 minus 2.

Step-by-step explanation:

Let p1 be the proportion of the common attribute in population1

And p2 be the proportion of the same common attribute in population2

: p1-p2=0

: p1-p2≠0

Test statistic can be found using the equation:

where

Then ≈ 2.03

p-value of the test statistic is  0.042>0.01, therefore we fail to reject the null hypothesis. There is no significant evidence that p1 is different than p2.

99% confidence interval estimate for p1-p2 can be calculated using the equation

p1-p2± where

Thus 99% confidence interval is

0.533-0.704± ≈ -0.171 ±0.237 that is (−0.408, 0.066)

can you put the picture up?

step-by-step explanation:

b and c

step-by-step explanation: