The population p (t) of a culture of bacteria is given by p (t) =-1710t +92,000t+10,000, where t is the time in hours since the culture was started. determine the time at which the population is at a maximum. round to the nearest hour.

The question might have some mistake since there are 2 multiplier of t. I found a similar question as follows:

The population P(t) of a culture of bacteria is given by P(t) = –1710t^2+ 92,000t + 10,000, where t is the time in hours since the culture was started. Determine the time at which the population is at a maximum. Round to the nearest hour.

27 hours

Step-by-step explanation:

Equation of population P(t) = –1710t^2+ 92,000t + 10,000

Find the derivative of the function to find the critical value

dP/dt = -2(1710)t + 92000

         = -3420t + 92000

Find the critical value by equating dP/dt = 0

-3420t + 92000 = 0

92000 = 3420t

t = 92000/3420 = 26.90

Check if it really have max value through 2nd derivative

d(dP)/dt^2 = -3420

2nd derivative is negative, hence it has maximum value

So, the time when it is maximum is 26.9 or 27 hours

g(x) is the negative form of f(x)? because whenever its the negative form it reflects its self over the x axis. idk if this is right though.

step-by-step explanation:

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