The mean maximum aerobic power (vo2max) score for women ages 20 to 29 is 36 ml/min/kg with a standard deviation of 7 ml/min/kg. find the probability of a woman between the ages of 20 to 29 having a vo2max score of greater than 45 ml/min/kg.

0.099 is the probability of a woman between the ages of 20 to 29 having a VO2MAX score of greater than 45 ml/min/kg.      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 36 ml/min/kg

Standard Deviation, σ = 7 ml/min/kg

We assume that the distribution of aerobic power is a bell shaped distribution that is a normal distribution.

Formula:

a) P(woman between the ages of 20 to 29 having a VO2MAX score of greater than 45 ml/min/kg.)

P(x > 45)

Calculation the value from standard normal z table, we have,  

0.099 is the probability of a woman between the ages of 20 to 29 having a VO2MAX score of greater than 45 ml/min/kg.

the answer would be c:   ax + b = ax + c

step-by-step explanation:

gmt is 4 hrs ahead of edt so just add four hours to 1: 14: 20 (minutes and seconds stay the same)

gmt is 5: 14: 20

hope this !

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