Nora uploaded a funny video on her website, which rapidly gains views over time. the following function gives the number of views ttt days after nora uploaded the video: v(t)=100⋅e0.4t what is the instantaneous rate of change of the number of views 444 days after the video was uploaded?

  about 198.1

Step-by-step explanation:

The instantaneous rate of change is given by the derivative:

  V'(t) = 100·e^(0.4t)(0.4)

  V'(t) = 40·e^(0.4t)

So V'(4) is ...

  V'(4) = 40·e^1.6 ≈ 198.1213

The instantaneous rate of change of views at day 4 is 198.1 views per day.

answer: i think it's a

step-by-step explanation: