Asample of 50 is selected from a known population of 250 elements. the population standard deviation is 15. using the finite correction factor, what is the standard error of the sample means?

standard error of mean r* = 1.90

Step-by-step explanation:

The Finite Correction Factor (FPC) is used when you sample without replacement from more than 5% of a finite population.

FPC = √[(N-n )/(N-1)]

N= population size = 250

n= sample size = 50

r* = standard error of mean

r = standard deviation = 15

FPC = √[(250-50)/(250-1)] = 0.896

Standard error of mean using FPC will be given as

r* = (r/√n) × FPC

r* = 15/√50 × 0.896

r* = 1.90

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!

sure i'm up for it

step-by-step explanation: