The length and width of a rectangle are consecutive even integers. the area of the rectangle is 48 square units. what are the length and width of the rectangle?

Let...

length=x+2

width=x

Equation: x(x+2)=48

x²+2x=48

x²+2x-48=0

(x+8)(x-6)=0

x=-8,6

But a length cannot be negative so... x=6.

The dimensions are 6 and 8.

The width is 6 and length is 8 units.

Step-by-step explanation:

Let x and x+2 be the integers.

Then: x(x + 2) = 48

x^2 + 2x - 48 = 0

(x - 6)(x + 8) = 0

x = 6, -8

Since the length and the width must be positive x = 6.

So the other side must be 8 , for the area to be 48.

y=mx+

answer: 2x + 2 − 2 = 10 − 2; subtraction property of equality

step-by-step explanation: