Acontractor is checking the height of the frame for a building his company is constructing. he stands at some distance from the building and measures the angle of elevation to be 73 degrees. he moves back 10 feet and measures the angle to be 68 degrees. how tall is the building?

  about 102 feet

Step-by-step explanation:

From the definition of the cotangent function, we can write ...

  h·cot(α1) = d1

  h·cot(α2) = d2

Where h is the building height and (α1, d1), (α2, d2) are (elevation angle, distance from the building) for the two cases.

We have d2 - d1 = 10 ft, so ...

  h(cot(68°) -cot(73°)) = 10 ft

  h = (10 ft)/(cot(68°) -cot(73°)) ≈ (10 ft)/(0.404026 -0.305731) ≈ 101.73 ft

The building is about 102 feet tall.

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations: