In this exercise, consider a particle moving on a circular path of radius b described by r(t) = b cos(ωt)i + b sin(ωt)j, where ω = du/dt is the constant angular velocity. find the acceleration vector and show that its direction is always toward the center of the circle.

Acceleration of the particle =

Step-by-step explanation:

We are given the position vector of a particle moving in a circle of radius b units.

r(t) = b cos(ωt)i + b sin(ωt)j

Velocity , v == -bω sin(ωt)i + bω cos(ωt)j

The magnitude of velocity, v =

Squaring both sides,

Since = 1

The acceleration towards the centre is called the centripetal acceleration and is given by

a =

a =

a =

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%

step-by-step explanation:

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