Use triangle abc with coordinates a(6,-2),b(-5,3), and c(1,4) to create a translation 3 units left and 2 units up. write the coordinates of each image in matrix form.

c.

Step-by-step explanation:

Given:

Vertex of triangle:

A(6,-2)

B(-5,3)

C(1,4)

The triangle ABC is translated 3 units left and 2 units up.

To find the co-ordinates of the vertex of the translated triangle in matrix form.

Solution:

Transformation sequence occurring can be given as:

3 units left shift would decrease the x-coordinate by 3 units.

2 units upwards shift would increase y-coordinate by 2 units.

So, we have

The Image points will be given as:

The image points in matrix form can be given as:

Plugging in the points the matrix can be written as:

(Answer)

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.