The number of pieces of mail that a department receives each day can be modeled by a distribution having mean 44 and standard deviation 8. for a random sample of 35 days, what can be said about the probability that the sample mean will be less than 40 or greater than 48 using?

Step-by-step explanation:

Assuming a normal distribution for the number of pieces of mail that a department receives each day, the formula for normal distribution is expressed as

z = (x - u)/s

Where

x = number of pieces of mail

u = mean

s = standard deviation

From the information given,

u = 44

s = 8

We want to find

P(x lesser than or 40) or P(x greater than 48)

For P(x lesser than or 40)

For x = 40,

z = (40 - 44)/8 = - 4/8 = - 0.5

Looking at the normal distribution table, the corresponding value of the z score is 0.30854

P(x greater than 48) = 1 - P(lesser than or or equal 48)

For x = 48,

z = (48 - 44)/8 = 4/8 = 0.5

Looking at the normal distribution table, the corresponding value of the z score is 0.69146

P(x greater than 48) = 1 - 0.69146 = 0.30854

The probability that the sample mean will be less than 40 or greater than 48 using is

0.30854 + 0.30854 = 0.69146

answer: there are x+184 pages in olivia's book.

step-by-step explanation:

let the total number of pages in the book which olive has already read be x.

then if olive has 184 pages left to read, then the total number of pages are in olive's book= pages she has read+pages she has left to read

therefore, the total number of pages in olivia's book=

hence, there are x+184 pages in olivia's book.

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right