Acar was travelling at a constant speed of 19 m/s, then accelerated for 10 seconds. the distance travelled, during this time, "d" metres, is given by the formula d = 19t + t^2, where "t" is the time in seconds since the acceleration began. how long did it take the car to travel 200m? give the answer to the nearest tenth of a second. solve algebraically.

7.5 seconds.

Step-by-step explanation:

Substitute the distace  220m in the given equation:

d = 19t + t^2

200 = 19t + t^2

t^2 + 19t - 200 = 0

t = [-19 +/- sqrt(19^2 - 4*1*-200)]  / 2

t = -19 +/- sqrt(1161) / 2

t = ( -19 +/- 34.07) / 2

t = 7.535 seconds

a) 0

step-by-step explanation:

i^413 x i^0 = 0 as any number multiplied by a zero is

happy to

pls mark as brainliest.

look at the picture.

y-intercept for the function on a picture is 4 → point (0, 4).

y-intercept for the function

is for x = 0. substitute:

y-intercept is 8 → point (0, 8).